1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
|
/********************************************************************
* Andrei Florea - CST116 - CH8 - Debugging
*
* File: CST116-Ch8-Debugging.cpp
*
* General Instructions: Complete each step before proceeding to the
* next.
*
* Debugging Exercise 1
*
* 1) Insert a breakpoint on the lines indicated in the code.
* 2) Run to Breakpoint 1.
* 3) Place a watch on i.
* 4) Execute the while statement by doing a "Step Into".
* 5) The execution continues to the cout statement as expected.
* 6) Step over the cout statement.
* 7) Why didn't the flow of the program return back to the while
* statement?
*
* The flow of the program did not return to the while statement because of the semicolon on the while statement,
* this is also explained in the next step. The brackets, which I thought had an error to do with the
* flow of the program not returning to the while statement do not matter here.
*
* 8) Fix this problem by removing the ; after the while statement.
* 9) Stop debugging and repeat Steps 2 � 5 to verify the correction
* worked.
*
* Done, however, debugging will now not enter the while block to execute the cout statement.
*
* 10) Stop debugging.
*
* Debugging Exercise 2
*
* 1) Run to Breakpoint 1.
* 2) Step into the while loop.
* 3) Why did the cout not execute?
*
* The cout did not execute because the while loop is comparing if the variable i is less than 0.
* However, the variable i is initialized as 0, and therefore is not less than 0, so it does not step
* into the while loop.
*
* 4) Check the value of i, now check the condition, does the
* condition evaluate to true?
* 5) Change the "< 0" to a "< 10".
* 6) Stop debugging and repeat Steps 1 � 4 to verify the correction
* worked.
*
* It works but it's an infinite loop.
*
* 7) Stop debugging.
*
* Debugging Exercise 3
*
* 1) Run the program without debugging.
* 2) What is happening now is an infinite loop.
* 3) End your program by holding down the Ctrl key and pressing C.
* 4) Fix the problem by adding a "++" after the i in the cout
* statement.
* 5) Run the program to Breakpoint 2 and verify that the output
* displayed on the screen is 0 � 9.
*
* Yes, if I add another breakpoint after the while loop block and run it in debug mode and check the console,
* the outputs are 0 to 9. However, the variable i is equal to 10, which makes sense because that is how it
* got out of the while loop block.
*
* Debugging Exercise 4
*
* 1) Run to Breakpoint 2.
* 2) Add a watch to the variable count.
* 3) Verify that the contents of count is garbage.
* 4) Step into the loop.
* 5) What is the value stored in count now?
*
* The value stored in count before was 1, but after stepping into the loop the value stored is now 10
*
* 6) Where was 10 assigned to count?
*
* I believe the 10 was assigned to count on line 99, where basically it just did a loop on that line without entering
* the line below, and it did it until count was equal to 10.
*
* 7) Fix the problem and re-run to verify.
*
* I fixed the problem, which was the same as the other loop with the semicolon on the for loop.
* I know the problem is fixed as I used the debugging tool and followed the flow of the code, entering
* the for loop until count was 10
*
* I am also adding curly brackets (which are not necessary as I found out) but it makes the code cleaner
* and easier to read.
*
********************************************************************/
#include <iostream>
using std::cout;
using std::endl;
int main()
{
int i = 0;
int count;
// Breakpoint 1
// Put a breakpoint on the following line
while (i < 10) {
cout << i++ << endl;
}
// Breakpoint 2
// Put a breakpoint on the following line
for (count = 0; count < 10; count++) {
cout << count << endl;
}
return 0;
}
|