From 22dfff41c7660a59f069af42d57c93f8939ff2c0 Mon Sep 17 00:00:00 2001
From: Andrei F <test@gmail.com>
Date: Wed, 19 Oct 2022 21:04:51 -0700
Subject: Added output and pseudo code, reformated file names, last commit

---
 CST116-Ch9-Debugging/CST116-Ch9-Debugging.cpp | 155 --------------------------
 1 file changed, 155 deletions(-)
 delete mode 100644 CST116-Ch9-Debugging/CST116-Ch9-Debugging.cpp

(limited to 'CST116-Ch9-Debugging/CST116-Ch9-Debugging.cpp')

diff --git a/CST116-Ch9-Debugging/CST116-Ch9-Debugging.cpp b/CST116-Ch9-Debugging/CST116-Ch9-Debugging.cpp
deleted file mode 100644
index 52afd58..0000000
--- a/CST116-Ch9-Debugging/CST116-Ch9-Debugging.cpp
+++ /dev/null
@@ -1,155 +0,0 @@
-/********************************************************************
- * Andrei Florea - CST 116 - Chapter 9 - Debugging & Functions
- *
- * Chapter 9 Questions & Answers (it didn't specify which questions, so I'm assuming all?)
- *  How does a computer know where to go back to?
- *      - It knows because of a parameter that is called the return address, which lets the computer know
- *      where to go back to after executing the function.
- *
- *  How does it maintain the state of all variables when a function is called?
- *      - The state of all variables is saved before a function call, and when creating a function,
- *      you can decide whether you want to pass the parameters as reference ( reference to the memory location )
- *      or passing the value of the variable which both can alter the original values, but they differ on how.
- *      Passing by reference, any manipulation inside the function to the given parameter variables will alter it,
- *      but if its passed by value, it has to return the variable(s), as it creates a copy of the original variables.
- *
- *
-* File: CST116-Ch9-Debugging.cpp
-*
-* General Instructions: Complete each step before proceeding to the
-* next.
-*
-* Debugging Exercise 1
-*
-* 1) Insert a breakpoint on the lines indicated in the code.
-* 2) Run to Breakpoint 1.
-* 3) Place a watch on age and days.
-* 4) Add another watch using &age for the name. This will display
-*    the address of age.
-* 5) Write down the address of age.
- *
- * 0x000000016dd67838
- *
-* 6) Step Into the code for the function GetAge.
-* 7) The execution continues to the function header for GetAge.
-* 8) Step into one more time.
-* 9) Why did the address of age and value change?
- *
- * The address of age and its value changed because we entered a function, where it initialized
- * a new variable with the same name, and gave it a different value. It is not overwriting the
- * original age variable, it is instead creating a new variable.
- *
-* 10) Step over the cout and cin statements.
-* 11) Verify the value entered is stored properly in age.
-* 12) Step into until the flow returns to main.
-* 13) Step over one more time.
-* 14) Why didn't the value entered get transferred back to main?
- *
- * The value entered didn't get transferred back to main because we are not
- * storing the return value of GetAge() to the variable age.
- *
-* 15) Stop debugging and fix the error.
-* 16) Run to Breakpoint 1.
-* 17) Step over the function call to GetAge.
-* 18) Verify that the value entered was returned and stored
-*     correctly from GetAge.
-* 19) Stop debugging.
- *
- * Done.
-*
-* Debugging Exercise 2
-*
-* 1) Run to Breakpoint 1.
-* 2) Step over the call to GetAge.
-* 3) Step into CalcDays.
-* 4) Step into one more time so that the current line is the
-*    calculation.
-* 5) Why is age greyed out in your watch window?
- *
- *  I believe age is greyed out in my watch window because we are not using the variable age to
- *  calculate the amount of days. It is now using the newly initialized variable in the parameter of
- *  CalcDays() which is "int years". So instead of age, I have years in my watch window.
- *
-* 6) Stop debugging.
-*
-* Debugging Exercise 3
-*
-* 1) Run to Breakpoint 2.
-* 2) When asked, enter the value of 20 for your age.
-* 3) Verify that the variable age is 20 and the variable days
-*    is 7300.
- *
- *    Verified.
- *
-* 4) Step into the PrintResults function.
-* 5) Age is 7300? Not even Ralph is that old.
-* 6) Why did the values for both variables change?
- *
- * The values changed because of the function call with the argument order. The function is defined
- * with the parameters in the order of (int days, int age). While the function call is calling
- * with the arguments of the variables in the order of (age, days).
- *
-* 7) Stop debugging and fix the error.
-*
-* Debugging Exercise 4
-*
-* 1) Run to Breakpoint 2.
-* 2) Display your Call Stack window.
-* 3) View the contents of the window and notice that the top
-*    function on the stack is main.
-* 4) Step into the PrintResults function.
-* 5) Notice that the call stack now shows PrintResults on top of
-*    the stack.
- *
- *    Done.
- *
-********************************************************************/
-#include <iostream>
-using std::cout;
-using std::cin;
-using std::endl;
-
-const int DAYS_PER_YEAR = 365;
-
-int GetAge();
-int CalcDays(int age);
-void PrintResults(int age, int days);
-
-int main()
-{
-    int age = 0;
-    int days = 0;
-
-    // Breakpoint 1
-    // Put breakpoint on the following line 
-    age = GetAge();
-    days = CalcDays(age);
-
-    // Breakpoint 2
-    // Put breakpoint on the following line
-    PrintResults(days, age);
-
-    return 0;
-}
-int GetAge()
-{
-    int age;
-
-    cout << "Please enter your age: ";
-    cin >> age;
-
-    return age;
-}
-int CalcDays(int years)
-{
-    int days;
-
-    days = years * DAYS_PER_YEAR;
-
-    return days;
-}
-void PrintResults(int days, int age)
-{
-    cout << age << "! Boy are you old!\n";
-    cout << "Did you know that you are at least " << days << " days old?\n\n";
-}
-- 
cgit v1.2.3