From 22dfff41c7660a59f069af42d57c93f8939ff2c0 Mon Sep 17 00:00:00 2001 From: Andrei F Date: Wed, 19 Oct 2022 21:04:51 -0700 Subject: Added output and pseudo code, reformated file names, last commit --- .../CST116-Ch9-Debugging-Florea.cpp | 155 +++++++++++++++++++++ 1 file changed, 155 insertions(+) create mode 100644 CST116-Ch9-Debugging/CST116-Ch9-Debugging-Florea.cpp (limited to 'CST116-Ch9-Debugging/CST116-Ch9-Debugging-Florea.cpp') diff --git a/CST116-Ch9-Debugging/CST116-Ch9-Debugging-Florea.cpp b/CST116-Ch9-Debugging/CST116-Ch9-Debugging-Florea.cpp new file mode 100644 index 0000000..52afd58 --- /dev/null +++ b/CST116-Ch9-Debugging/CST116-Ch9-Debugging-Florea.cpp @@ -0,0 +1,155 @@ +/******************************************************************** + * Andrei Florea - CST 116 - Chapter 9 - Debugging & Functions + * + * Chapter 9 Questions & Answers (it didn't specify which questions, so I'm assuming all?) + * How does a computer know where to go back to? + * - It knows because of a parameter that is called the return address, which lets the computer know + * where to go back to after executing the function. + * + * How does it maintain the state of all variables when a function is called? + * - The state of all variables is saved before a function call, and when creating a function, + * you can decide whether you want to pass the parameters as reference ( reference to the memory location ) + * or passing the value of the variable which both can alter the original values, but they differ on how. + * Passing by reference, any manipulation inside the function to the given parameter variables will alter it, + * but if its passed by value, it has to return the variable(s), as it creates a copy of the original variables. + * + * +* File: CST116-Ch9-Debugging.cpp +* +* General Instructions: Complete each step before proceeding to the +* next. +* +* Debugging Exercise 1 +* +* 1) Insert a breakpoint on the lines indicated in the code. +* 2) Run to Breakpoint 1. +* 3) Place a watch on age and days. +* 4) Add another watch using &age for the name. This will display +* the address of age. +* 5) Write down the address of age. + * + * 0x000000016dd67838 + * +* 6) Step Into the code for the function GetAge. +* 7) The execution continues to the function header for GetAge. +* 8) Step into one more time. +* 9) Why did the address of age and value change? + * + * The address of age and its value changed because we entered a function, where it initialized + * a new variable with the same name, and gave it a different value. It is not overwriting the + * original age variable, it is instead creating a new variable. + * +* 10) Step over the cout and cin statements. +* 11) Verify the value entered is stored properly in age. +* 12) Step into until the flow returns to main. +* 13) Step over one more time. +* 14) Why didn't the value entered get transferred back to main? + * + * The value entered didn't get transferred back to main because we are not + * storing the return value of GetAge() to the variable age. + * +* 15) Stop debugging and fix the error. +* 16) Run to Breakpoint 1. +* 17) Step over the function call to GetAge. +* 18) Verify that the value entered was returned and stored +* correctly from GetAge. +* 19) Stop debugging. + * + * Done. +* +* Debugging Exercise 2 +* +* 1) Run to Breakpoint 1. +* 2) Step over the call to GetAge. +* 3) Step into CalcDays. +* 4) Step into one more time so that the current line is the +* calculation. +* 5) Why is age greyed out in your watch window? + * + * I believe age is greyed out in my watch window because we are not using the variable age to + * calculate the amount of days. It is now using the newly initialized variable in the parameter of + * CalcDays() which is "int years". So instead of age, I have years in my watch window. + * +* 6) Stop debugging. +* +* Debugging Exercise 3 +* +* 1) Run to Breakpoint 2. +* 2) When asked, enter the value of 20 for your age. +* 3) Verify that the variable age is 20 and the variable days +* is 7300. + * + * Verified. + * +* 4) Step into the PrintResults function. +* 5) Age is 7300? Not even Ralph is that old. +* 6) Why did the values for both variables change? + * + * The values changed because of the function call with the argument order. The function is defined + * with the parameters in the order of (int days, int age). While the function call is calling + * with the arguments of the variables in the order of (age, days). + * +* 7) Stop debugging and fix the error. +* +* Debugging Exercise 4 +* +* 1) Run to Breakpoint 2. +* 2) Display your Call Stack window. +* 3) View the contents of the window and notice that the top +* function on the stack is main. +* 4) Step into the PrintResults function. +* 5) Notice that the call stack now shows PrintResults on top of +* the stack. + * + * Done. + * +********************************************************************/ +#include +using std::cout; +using std::cin; +using std::endl; + +const int DAYS_PER_YEAR = 365; + +int GetAge(); +int CalcDays(int age); +void PrintResults(int age, int days); + +int main() +{ + int age = 0; + int days = 0; + + // Breakpoint 1 + // Put breakpoint on the following line + age = GetAge(); + days = CalcDays(age); + + // Breakpoint 2 + // Put breakpoint on the following line + PrintResults(days, age); + + return 0; +} +int GetAge() +{ + int age; + + cout << "Please enter your age: "; + cin >> age; + + return age; +} +int CalcDays(int years) +{ + int days; + + days = years * DAYS_PER_YEAR; + + return days; +} +void PrintResults(int days, int age) +{ + cout << age << "! Boy are you old!\n"; + cout << "Did you know that you are at least " << days << " days old?\n\n"; +} -- cgit v1.2.3